// Programmieren 1, Praktikum 3, Aufgabe 2
// Sven Eisenhauer
// 12.11.2004
//
// file: main.cpp
//
// purpose: roll 2 dice 6000 times and build a table, how often each possible sum occured
//          
//          
//          
//
#include <iostream>
using std::cin;
using std::cout;
using std::endl;

#include <ctime>
#include <cstdlib>

int rollDice(void);

int main ()
{
	int stats[13] = {0};

    srand(time(0));

	for (int Counter=0;Counter <= 6000;Counter++)
	{
		/* switch (rollDice())
		{
			case 2:
				stats[0]++;
				break;
			case 3:
				stats[1]++;
				break;
			case 4:
				stats[2]++;
				break;
			case 5:
				stats[3]++;
				break;
			case 6:
				stats[4]++;
				break;
			case 7:
				stats[5]++;
				break;
			case 8:
				stats[6]++;
				break;
			case 9:
				stats[7]++;
				break;
			case 10:
				stats[8]++;
				break;
			case 11:
				stats[9]++;
				break;
			case 12:
				stats[10]++;
				break;
			default:
				cout << "Uuups... we should never get here...";
		}*/
		++stats[rollDice()];
	}
	for (int i=2;i<=12;i++)
	{
		cout << endl << i << ": " << stats[i];
	}
	cout << endl;
	return 0;
}

int rollDice(void)
{
	return (( 1 + (rand() % 6)) + ( 1 + (rand() % 6)));
}