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// Programmieren 1, Praktikum 3, Aufgabe 2
// Sven Eisenhauer
// 12.11.2004
//
// file: main.cpp
//
// purpose: roll 2 dice 6000 times and build a table, how often each possible sum occured
//
//
//
//
#include <iostream>
using std::cin;
using std::cout;
using std::endl;
#include <ctime>
#include <cstdlib>
int rollDice(void);
int main ()
{
int stats[13] = {0};
srand(time(0));
for (int Counter=0;Counter <= 6000;Counter++)
{
/* switch (rollDice())
{
case 2:
stats[0]++;
break;
case 3:
stats[1]++;
break;
case 4:
stats[2]++;
break;
case 5:
stats[3]++;
break;
case 6:
stats[4]++;
break;
case 7:
stats[5]++;
break;
case 8:
stats[6]++;
break;
case 9:
stats[7]++;
break;
case 10:
stats[8]++;
break;
case 11:
stats[9]++;
break;
case 12:
stats[10]++;
break;
default:
cout << "Uuups... we should never get here...";
}*/
++stats[rollDice()];
}
for (int i=2;i<=12;i++)
{
cout << endl << i << ": " << stats[i];
}
cout << endl;
return 0;
}
int rollDice(void)
{
return (( 1 + (rand() % 6)) + ( 1 + (rand() % 6)));
}
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