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// Programmieren 1, Praktikum 3, Aufgabe 4
// Sven Eisenhauer
// 17.11.2004
//
// file: main.cpp
//
// purpose: find the greatest common divisor of two numbers, recursive...
//
//
#include <iostream>
using std::cin;
using std::cout;
using std::endl;
int gcd(int,int);
int main()
{
int number1,
number2;
cout << "1st number: ";
cin >> number1;
cout << "2nd number: ";
cin >> number2;
cout <<endl<<"Greatest common divisor: "<< gcd(number1,number2) << endl;
return 0;
}
int gcd(int x, int y)
{
if (0 == y)
{
return x;
}
else
{
return gcd (y,x%y);
}
}
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